| | |
| | | }, |
| | | |
| | | /** |
| | | * 获取两个经纬度之间的角度(0度-360度) |
| | | */ |
| | | getAngle(lng_a, lat_a, lng_b, lat_b) { |
| | | var a = ((90 - lat_b) * Math.PI) / 180; |
| | | var b = ((90 - lat_a) * Math.PI) / 180; |
| | | var AOC_BOC = ((lng_b - lng_a) * Math.PI) / 180; |
| | | var cosc = |
| | | Math.cos(a) * Math.cos(b) + Math.sin(a) * Math.sin(b) * Math.cos(AOC_BOC); |
| | | var sinc = Math.sqrt(1 - cosc * cosc); |
| | | var sinA = (Math.sin(a) * Math.sin(AOC_BOC)) / sinc; |
| | | var A = (Math.asin(sinA) * 180) / Math.PI; |
| | | var res = 0; |
| | | if (lng_b > lng_a && lat_b > lat_a) res = A; |
| | | else if (lng_b > lng_a && lat_b < lat_a) res = 180 - A; |
| | | else if (lng_b < lng_a && lat_b < lat_a) res = 180 - A; |
| | | else if (lng_b < lng_a && lat_b > lat_a) res = 360 + A; |
| | | else if (lng_b > lng_a && lat_b == lat_a) res = 90; |
| | | else if (lng_b < lng_a && lat_b == lat_a) res = 270; |
| | | else if (lng_b == lng_a && lat_b > lat_a) res = 0; |
| | | else if (lng_b == lng_a && lat_b < lat_a) res = 180; |
| | | return res; |
| | | }, |
| | | |
| | | /** |
| | | * 获取两经纬度间的距离 |
| | | */ |
| | | getDistance(lng1, lat1, lng2, lat2) { |
| | | lat1 = lat1 || 0; |
| | | lng1 = lng1 || 0; |
| | | lat2 = lat2 || 0; |
| | | lng2 = lng2 || 0; |
| | | |
| | | var rad1 = (lat1 * Math.PI) / 180.0; |
| | | var rad2 = (lat2 * Math.PI) / 180.0; |
| | | var a = rad1 - rad2; |
| | | var b = (lng1 * Math.PI) / 180.0 - (lng2 * Math.PI) / 180.0; |
| | | var r = 6378137; |
| | | var distance = |
| | | r * |
| | | 2 * |
| | | Math.asin( |
| | | Math.sqrt( |
| | | Math.pow(Math.sin(a / 2), 2) + |
| | | Math.cos(rad1) * Math.cos(rad2) * Math.pow(Math.sin(b / 2), 2) |
| | | ) |
| | | ); |
| | | |
| | | return distance; |
| | | }, |
| | | |
| | | /** |
| | | * 将二维数组形式的坐标点数组转换为高德地图中 LngLat 类 |
| | | * @param {*} lnglats |
| | | * @returns |
| | |
| | | let mglng = Math.round((lng * 2 - lng - dlng) * 1000000) / 1000000; |
| | | return [mglng, mglat]; |
| | | } |
| | | }, |
| | | |
| | | //从GPS转高德 |
| | | wgs84_To_Gcj02(lon, lat) { |
| | | if (out_of_china(lon, lat)) { |
| | | return [lon, lat]; |
| | | } else { |
| | | let dLat = transformlat(lon - 105.0, lat - 35.0); |
| | | let dLon = transformlng(lon - 105.0, lat - 35.0); |
| | | let radLat = (lat / 180.0) * PI; |
| | | let magic = Math.sin(radLat); |
| | | magic = 1 - ee * magic * magic; |
| | | let sqrtMagic = Math.sqrt(magic); |
| | | dLat = (dLat * 180.0) / (((a * (1 - ee)) / (magic * sqrtMagic)) * PI); |
| | | dLon = (dLon * 180.0) / ((a / sqrtMagic) * Math.cos(radLat) * PI); |
| | | let mgLat = lat + dLat; |
| | | let mgLon = lon + dLon; |
| | | return [mgLon, mgLat]; |
| | | } |
| | | } |
| | | }; |